Best ‘Foodie Cities’ In America: Here’s Where Cleveland Ranks

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Where does Cleveland rank among the best foodie cities in America?

The term ‘foodie’ has been around since the 80s, but you may have a hard time explaining that to your TikTok and Instagram celebrity friends. Scrolling through your smartphone may have you convinced that only the finest local eateries would qualify for such a prestigious term, but that’s not always the case.

Any person with a keen interest in food, whether cooking or eating it, can be considered a foodie. The restaurant scene in Northeast Ohio is immaculate, which makes it easy for foodies to thrive here.

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And, it’s not just us. America is ripe with ‘foodie’ cities. From coast to coast, each region has its own special offerings and local faves.

In a recent list put together by WalletHub, the top foodie cities in America were ranked. Using a combination of 28 “key indicators”, they examined varying factors in 180 U.S. cities.

Where do you think Cleveland ended up on the list?

The #1 ranked foodie city in America is Miami, Florida. While their Affordability rank was not very good (#145), their Diversity, Accessibility, and Quality rank was #1.

Following Miami were San Francisco (#2), Orlando (#3), Portland (#4) and Tampa (#5).

Ohio Ranks

So where does Ohio rank in terms of the best foodie cities in America?

The highest-ranked city in Ohio was Cincinnati (#22). Cleveland came in at #50, while being #70 in Affordability and #52 in Diversity, Accessibility, and Quality.

The only other Ohio cities to make the list were Toledo (#97) and Akron (#147).

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